Given:
p = 3, α = tan-1 (\( \dfrac{5}{12}\))
So, tan α = \( \dfrac{5}{12}\)
sin α = \( \dfrac{5}{13}\)
cos α = \( \dfrac{12}{13}\)
The equation of the line in normal form is given by
By using the formula,
x cos α + y sin α = p
Now, substitute the values, we get
\( \dfrac{12x}{13}+ \dfrac{5y}{13}=3\)
12x + 5y = 39
The equation of line in normal form is 12x + 5y = 39.
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