Given:
p = 2, sin α = \( \dfrac{1}{3}\)
We know that cos α = \( \sqrt{(1 – sin^2 α)}\)
= \( \sqrt{(1 – \dfrac{1}{9}})\)
= \( \dfrac{2\sqrt{2}}{3}\)
The equation of the line in normal form is given by
By using the formula,
x cos α + y sin α = p
Now, substitute the values, we get
\( \dfrac{x^2\sqrt{2}}{3}+\dfrac{y}{3}=2\)
\( 2\sqrt{2}x + y = 6\)
The equation of line in normal form is \( 2\sqrt{2}x + y = 6\)
Answered by Aaryan | 1 year agoFind the angle between the line joining the points (2, 0), (0, 3) and the line x + y = 1.
Prove that the points (2, -1), (0, 2), (2, 3) and (4, 0) are the coordinates of the vertices of a parallelogram and find the angle between its diagonals.
Find the acute angle between the lines 2x – y + 3 = 0 and x + y + 2 = 0.
Find the angles between pairs of straight lines 3x – y + 5 = 0 and x – 3y + 1 = 0
Find the angles between pairs of straight lines 3x + y + 12 = 0 and x + 2y – 1 = 0