Given:
Points (2, 0), (0, 3) and the line x + y = 1.
Let us assume A (2, 0), B (0, 3) be the given points.
Now, let us find the slopes
Slope of AB = m1
= \(\dfrac{ (3-0) }{ (0-2)}\)
= \( \dfrac{-3}{2}\)
Slope of the line x + y = 1 is -1
m2 = -1
Let θ be the angle between the line joining the points (2, 0), (0, 3) and the line x + y =
\( \dfrac{ ( \dfrac{-3}{2}+1)}{ ( \dfrac{-3}{2}+1)}\)
=\( \dfrac{1}{5}\)
θ = tan-1(\( \dfrac{1}{5}\))
The acute angle between the line joining the points (2, 0), (0, 3) and the line x + y = 1 is tan-1 (\( \dfrac{1}{5}\)).
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