Find the angle between the line joining the points (2, 0), (0, 3) and the line x + y = 1.

Asked by Sakshi | 1 year ago |  117

##### Solution :-

Given:

Points (2, 0), (0, 3) and the line x + y = 1.

Let us assume A (2, 0), B (0, 3) be the given points.

Now, let us find the slopes

Slope of AB = m1

= $$\dfrac{ (3-0) }{ (0-2)}$$

$$\dfrac{-3}{2}$$

Slope of the line x + y = 1 is -1

m2 = -1

Let θ be the angle between the line joining the points (2, 0), (0, 3) and the line x + y =

$$\dfrac{ ( \dfrac{-3}{2}+1)}{ ( \dfrac{-3}{2}+1)}$$

=$$\dfrac{1}{5}$$

θ = tan-1($$\dfrac{1}{5}$$)

The acute angle between the line joining the points (2, 0), (0, 3) and the line x + y = 1 is tan-1 ($$\dfrac{1}{5}$$).

Answered by Aaryan | 1 year ago

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