Find the equation of the circle with Centre (–2, 3) and radius 4

Asked by Aaryan | 2 years ago |  111

##### Solution :-

Given:

Centre (-2, 3) and radius 4

Let us consider the equation of a circle with centre (h, k) and

Radius r is given as (x – h)+ (y – k)= r2

So, centre (h, k) = (-2, 3) and radius (r) = 4

The equation of the circle is

(x + 2)2 + (y – 3)2 = (4)2

x2 + 4x + 4 + y2 – 6y + 9 = 16

x2 + y2 + 4x – 6y – 3 = 0

The equation of the circle is x2 + y2 + 4x – 6y – 3 = 0

Answered by Sakshi | 2 years ago

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