Given:
Centre (-a, -b) and radius \( \sqrt{(a^2 – b^2)}\)
Let us consider the equation of a circle with centre (h, k) and
Radius r is given as (x – h)2 + (y – k)2 = r2
So, centre (h, k) = (-a, -b) and radius (r) = \( \sqrt{(a^2 – b^2)}\)
The equation of the circle is
(x + a)2 + (y + b)2 = \( (\sqrt{(a^2 – b^2)^2)}\)
x2 + 2ax + a2 + y2 + 2by + b2 = a2 – b2
x2 + y2 +2ax + 2by + 2b2 = 0
The equation of the circle is x2 + y2 +2ax + 2by + 2b2 = 0
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