Given:
The equation of the given circle is x2 + y2 – 4x – 8y – 45 = 0.
x2 + y2 – 4x – 8y – 45 = 0
(x2 – 4x) + (y2 -8y) = 45
(x2 – 2(x) (2) + 22) + (y2 – 2(y) (4) + 42) – 4 – 16 = 45
(x – 2)2 + (y – 4)2 = 65
(x – 2)2 + (y – 4)2 = \( ( \sqrt{65})^2\) [which is form (x-h)2 +(y-k)2 = r2]
Where h = 2, K = 4 and r = \( \sqrt{65}\)
The centre of the given circle is (2, 4) and its radius is \( \sqrt{65}\)
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