The equation of the given of the circle is 2x2 + 2y2 –x = 0.
2x2 + 2y2 –x = 0
(2x2 + x) + 2y2 = 0
(x2 – 2 (x) (\( \dfrac{1}{4}\)) + (\( \dfrac{1}{4}\))2) + y2 – (\( \dfrac{1}{4}\))2 = 0
(x – \( \dfrac{1}{4}\))2 + (y – 0)2 = (\( \dfrac{1}{4}\))2 [which is form (x-h)2 +(y-k)2 = r2]
Where, h = \( \dfrac{1}{4}\), K = 0
The center of the given circle is (\( \dfrac{1}{4}\), 0) and its radius is \( \dfrac{1}{4}\).
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