Find the centre and radius of the circles 2x2 + 2y2 – x = 0

Asked by Aaryan | 1 year ago |  91

Solution :-

The equation of the given of the circle is 2x2 + 2y2 –x = 0.

2x2 + 2y2 –x = 0

(2x2 + x) + 2y2 = 0

(x2 – 2 (x) ($$\dfrac{1}{4}$$) + ($$\dfrac{1}{4}$$)2) + y2 – ($$\dfrac{1}{4}$$)2 = 0

(x – $$\dfrac{1}{4}$$)2 + (y – 0)2 = ($$\dfrac{1}{4}$$)2 [which is form (x-h)2 +(y-k)2 = r2]

Where, h = $$\dfrac{1}{4}$$, K = 0

The center of the given circle is ($$\dfrac{1}{4}$$, 0) and its radius is $$\dfrac{1}{4}$$.

Answered by Aaryan | 1 year ago

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