Given:
The equation of the given circle is x2 +y2 = 25.
x2 + y2 = 25
(x – 0)2 + (y – 0)2 = 52 [which is of the form (x – h)2 + (y – k)2 = r2]
Where, h = 0, k = 0 and r = 5.
So the distance between point (-2.5, 3.5) and the centre (0,0) is
= \( \sqrt{(-2.5 – 0)^2 + (-3.5 – 0)^2}\)
= \( \sqrt{(6.25 + 12.25)}\)
= \( \sqrt{18.5}\)
= 4.3 [which is < 5]
Since, the distance between point (-2.5, -3.5) and the centre (0, 0) of the circle is less than the radius of the circle, point (-2.5, -3.5) lies inside the circle.
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