Given:
Vertices (0, ± 13) and foci (0, ± 5)
Here, the vertices are on the y-axis.
Then, a =13 and c = 5.
It is known that a2 = b2 + c2.
132 = b2+52
169 = b2 + 15
b2 = 169 – 125
b =\( \sqrt{144}\)
= 12
The equation of the ellipse is \(\dfrac{ x^2}{12^2} + \dfrac{y^2}{13^2} = 1\)
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