Find the equation for the ellipse that satisfies the given conditions Vertices (0, ± 13), foci (0, ± 5)

Asked by Sakshi | 1 year ago |  57

##### Solution :-

Given:

Vertices (0, ± 13) and foci (0, ± 5)

Here, the vertices are on the y-axis.

Then, a =13 and c = 5.

It is known that a2 = b+ c2.

132 = b2+52

169 = b2 + 15

b2 = 169 – 125

b =$$\sqrt{144}$$

= 12

The equation of the ellipse is $$\dfrac{ x^2}{12^2} + \dfrac{y^2}{13^2} = 1$$

Answered by Aaryan | 1 year ago

### Related Questions

#### An equilateral triangle is inscribed in the parabola y2 = 4ax,

An equilateral triangle is inscribed in the parabola y2 = 4ax, where one vertex is at the vertex of the parabola. Find the length of the side of the triangle.

#### A man running a racecourse notes that the sum of the distances from the two flag posts from him is always

A man running a racecourse notes that the sum of the distances from the two flag posts from him is always 10 m and the distance between the flag posts is 8 m. Find the equation of the posts traced by the man.

#### Find the area of the triangle formed by the lines joining the vertex of the parabola x2 = 12y to the ends

Find the area of the triangle formed by the lines joining the vertex of the parabola x2 = 12y to the ends of its latus rectum.