Find the equation for the ellipse that satisfies the given conditions Length of minor axis 16, foci (0, ±6).

Asked by Sakshi | 1 year ago |  56

##### Solution :-

Given:

Length of minor axis is 16 and foci (0, ±6).

Since the foci are on the y-axis, the major axis is along the y-axis.

Then, 2b =16

b = 8 and c = 6.

It is known that a2 = b+ c2.

a2 = 8+ 62

= 64 + 36

=100

a = $$\sqrt{100}$$

= 10

The equation of the ellipse is $$\dfrac{ x^2}{8^2} + \dfrac{y^2}{10^2} =1$$

Answered by Aaryan | 1 year ago

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