Given:
Length of minor axis is 16 and foci (0, ±6).
Since the foci are on the y-axis, the major axis is along the y-axis.
Then, 2b =16
b = 8 and c = 6.
It is known that a2 = b2 + c2.
a2 = 82 + 62
= 64 + 36
=100
a = \( \sqrt{100}\)
= 10
The equation of the ellipse is \(\dfrac{ x^2}{8^2} + \dfrac{y^2}{10^2} =1 \)
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