Find the 7th term in the expansion of (3x2 – 1/x3)10.

Question

Find the \( 7^{th}\) term in the expansion of \( (3x^2 – \dfrac{1}{x^3})^{10}\)

Asked by Sakshi | 1 year ago | 73

0 0

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Accepted Answer

Let us consider the 7^th term as T₇

So,

T₇ = T₆₊₁

= ¹⁰C₆ (3x²)^10-6 (\( \dfrac{-1}{x^3}\))⁶

= ¹⁰C₆ (3)⁴ (x)⁸ (\( \dfrac{1}{x^{18}}\))

= \(\dfrac{10×9×8×7×81}{ 4×3×2×x^{10}}\)

= \(\dfrac{ 17010 }{ x^{10}}\)

The 7^th term of the expression is \( \dfrac{ 17010 }{ x^{10}}\)

Answered by Sakshi | 1 year ago