Find the \( 7^{th}\) term in the expansion of \( (3x^2 – \dfrac{1}{x^3})^{10}\)

Asked by Sakshi | 1 year ago |  105

1 Answer

Solution :-

Let us consider the 7th term as T7

So,

T7 = T6+1

10C6 (3x2)10-6 (\( \dfrac{-1}{x^3}\))6

10C6 (3)4 (x)8 (\( \dfrac{1}{x^{18}}\))

= \(\dfrac{10×9×8×7×81}{ 4×3×2×x^{10}}\)

= \(\dfrac{ 17010 }{ x^{10}}\)

The 7th term of the expression is \( \dfrac{ 17010 }{ x^{10}}\)

Answered by Sakshi | 1 year ago

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