Find the 8th term in the expansion of (x3/2 y1/2 – x1/2 y3/2)10.

Question

Find the \( 8^{th}\) term in the expansion of \( (x^{\dfrac{3}{2}} y^{\dfrac{1}{2}} – x^{\dfrac{1}{2}} y^{\dfrac{3}{2}})^{10}\)

Asked by Sakshi | 1 year ago | 53

0 0

Class 11 Maths Binomial Theorem Add Answer

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Accepted Answer

Let us consider the 8^th term as T₈

So,

T₈ = T₇₊₁

= \( ( \dfrac{-10×9×8}{3×2}) x^{\dfrac{9}{2}} y^{\dfrac{3}{2}} (x^{\dfrac{7}{2}} y^{\dfrac{21}{2}})\)

= -120 x⁸y¹²

The 8^th term of the expression is -120 x⁸y¹².

Answered by Sakshi | 1 year ago