If x occurs at the (r + 1)th term in the given expression.
Then, we have:
(1 – 2x3 + 3x5) (1 + \( \dfrac{1}{x}\))8
So, ‘x’ occurs in the above expression at -2x3.8C2 (\( \dfrac{1}{x^2}\)) + 3x5.8C4 (\( \dfrac{1}{x^4}\))
Coefficient of x =\( -2 (\dfrac{8!}{(2!6!) })+ 3 (\dfrac{8!}{(4! 4!)})\)
= -56 + 210
= 154
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