Find the middle term in the expansion of \( (\dfrac{a}{x} + bx)^{12}\)

Asked by Sakshi | 1 year ago |  63

1 Answer

Solution :-

We have,

where, n = 12 (even number)

So the middle term is (\( \dfrac{n}{2}\) + 1)

= (\( \dfrac{12}{2}\) + 1)

= (6 + 1) = 7. ie., 7th term

Now,

T7 = T6+1

RD Sharma Solutions for Class 11 Maths Chapter 18 – Binomial Theorem image - 38

= 924 a6b6

Hence, the middle term is 924 a6b6.

Answered by Sakshi | 1 year ago

Related Questions

Find the term independent of x in the expansion of \( (\dfrac{3}{2x^2} – \dfrac{1}{3x})^9\)

Class 11 Maths Binomial Theorem View Answer

Find the middle term in the expansion of \((x-\dfrac{ 1}{x})^{2n+1}\)

Class 11 Maths Binomial Theorem View Answer

Find the middle term in the expansion of (1 + 3x + 3x2 + x3)2n

Class 11 Maths Binomial Theorem View Answer

Find the middle term in the expansion of \( (\dfrac{x}{a} – \dfrac{a}{x})^{10}\)

Class 11 Maths Binomial Theorem View Answer