Find the middle term in the expansion of (1 – 2x + x2)n

Asked by Aaryan | 1 year ago |  179

##### Solution :-

We have,

(1 – 2x + x2)n = (1 – x)2n where, n is an even number.

So the middle term is ($$\dfrac{2n}{2}$$ + 1) = (n + 1)th term.

Now,

Tn = Tn+1

2nCn (-1)n (x)n

= $$\dfrac{(2n)!}{(n!)^2} (-1)^n x^n$$

Hence, the middle term is $$\dfrac{(2n)!}{(n!)^2} (-1)^n x^n$$

Answered by Sakshi | 1 year ago

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