The lengths (in cm) of 10 rods in a shop are 40.0, 52.3, 55.2, 72.9, 52.8, 79.0, 32.5, 15.2, 27.9, 30.2 . Find the mean deviation from the mean also.

Asked by Sakshi | 1 year ago |  73

##### Solution :-

Find the mean deviation from the mean also.

We know that,

Where, |di| = |xi – x|

So, let ‘x’ be the mean of the given observation.

x =

$$\dfrac{ [40.0 + 52.3 + 55.2 + 72.9 + 52.8 + 79.0 + 32.5 + 15.2 + 27.9 + 30.2]}{10}$$

$$\dfrac{458}{10}$$

= 45.8

Number of observations, ‘n’ = 10

= $$\dfrac{1}{10}$$ × 166.4

= 16.64

The Mean Deviation is 16.64

Answered by Aaryan | 1 year ago

### Related Questions

#### Find the mean deviation from the mean and from a median of the following distribution

Find the mean deviation from the mean and from a median of the following distribution:

 Marks 0-10 10-20 20-30 30-40 40-50 No. of students 5 8 15 16 6

#### The age distribution of 100 life-insurance policy holders is as follows:

The age distribution of 100 life-insurance policy holders is as follows

 Age (on nearest birthday) 17-19.5 20-25.5 26-35.5 36-40.5 41-50.5 51-55.5 56-60.5 61-70.5 No. of persons 5 16 12 26 14 12 6 5

#### Compute mean deviation from mean of the following distribution:

Compute mean deviation from mean of the following distribution:

 Marks 10-20 20-30 30-40 40-50 50-60 60-70 70-80 80-90 No. of students 8 10 15 25 20 18 9 5

#### Find the mean deviation from the mean for the following data

Find the mean deviation from the mean for the following data:

 Classes 95-105 105-115 115-125 125-135 135-145 145-155 Frequencies 9 13 16 26 30 12