1 Answer
Solution :-
To find the mean deviation from the mean, firstly let us calculate the mean.
By using the formula,
\( x= \dfrac{\displaystyle\sum fixi}{fi}\)
_1650796301.bmp)
\( x= \dfrac{\displaystyle\sum f_ix_i}{f_i}\)
= \(\dfrac{ 4000}{80}\)
= 50
\( x= \dfrac{\displaystyle\sum f_i|d_i|}{f_i}\)
= \( \dfrac{1280}{80}\)
= 16
The mean deviation is 16
Answered by Aaryan | 1 year agoRelated Questions
Find the mean deviation from the mean and from a median of the following distribution:
| Marks | 0-10 | 10-20 | 20-30 | 30-40 | 40-50 |
| No. of students | 5 | 8 | 15 | 16 | 6 |
The age distribution of 100 life-insurance policy holders is as follows
| Age (on nearest birthday) | 17-19.5 | 20-25.5 | 26-35.5 | 36-40.5 | 41-50.5 | 51-55.5 | 56-60.5 | 61-70.5 |
| No. of persons | 5 | 16 | 12 | 26 | 14 | 12 | 6 | 5 |
Compute mean deviation from mean of the following distribution:
| Marks | 10-20 | 20-30 | 30-40 | 40-50 | 50-60 | 60-70 | 70-80 | 80-90 |
| No. of students | 8 | 10 | 15 | 25 | 20 | 18 | 9 | 5 |
Find the mean deviation from the mean for the following data:
| Classes | 95-105 | 105-115 | 115-125 | 125-135 | 135-145 | 145-155 |
| Frequencies | 9 | 13 | 16 | 26 | 30 | 12 |
Find the mean deviation from the mean for the following data:
| Classes | 0-100 | 100-200 | 200-300 | 300-400 | 400-500 | 500-600 | 600-700 | 700-800 |
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