As we know that total surface area of cylinder = 2πr2 + 2πrh
Given as the radius of cylinder varies
So, find \( \dfrac{ds}{dr}\)
Here, s = surface area of cylinder and r = radius of cylinder.
\( \dfrac{ds}{dr}\) = 4πr + 2πh
Thus, rate of change of tatal surface area of cylinder when the radius is varying given by (4πr + 2πh).
Answered by Sakshi | 1 year agoGiven the sum of the perimeters of a square and a circle, show that the sum of their areas is least when one side of the square is equal to diameter of the circle.
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