The side of a square is increasing at the rate of 0.2 cm/sec. Find the rate of increase of the perimeter of the square.

Asked by Aaryan | 1 year ago |  67

##### Solution :-

Given the side of a square is increasing at the rate of 0.2 cm/sec.

To find rate of increase of the perimeter of the square

Let the edge of the given cube be x cm at any instant time.

Then according to the given question, we can write as

The rate of side of the square increasing is, $$\dfrac{dx}{dt}$$ = 0.2 cm/sec ...(i)

Now the perimeter of the square at any time t will be  P = 4x cm

By applying derivative with respect to time on both sides

$$\dfrac{dP}{dt}=4\times 0.2$$

=0.8 cm/sec

From the equation (i)

Thus the rate of increasing of the perimeter of the square will be 0.8 cm/sec.

Answered by Sakshi | 1 year ago

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