Given f(x) = – (x – 1)^{2} + 2

It can be observed that (x – 1)^{2 }≥ 0 for every x ∈ R

Therefore, f(x) = – (x – 1)^{2} + 2 ≤ 2 for every x ∈ R

The maximum value of f is attained when (x – 1) = 0

(x – 1) = 0, x = 1

Since, Maximum value of f = f (1) = – (1 – 1)^{2} + 2 = 2

Hence, function f does not have minimum value.

Answered by Aaryan | 1 year agoGiven the sum of the perimeters of a square and a circle, show that the sum of their areas is least when one side of the square is equal to diameter of the circle.

A wire of length 20 m is to be cut into two pieces. One of the pieces will be bent into shape of a square and the other into shape of an equilateral triangle. Where the wire should be cut so that the sum of the areas of the square and triangle is minimum?

A wire of length 28 m is to be cut into two pieces. One of the pieces is to be made into a square and the other into a circle. What should be the lengths of the two pieces so that the combined area of the circle and the square is minimum?

Of all the closed cylindrical cans (right circular), which enclose a given volume of 100 cm^{3}, which has the minimum surface area?

Divide 15 into two parts such that the square of one multiplied with the cube of the other is minimum.