Given f(x) = – (x – 1)2 + 2
It can be observed that (x – 1)2 ≥ 0 for every x ∈ R
Therefore, f(x) = – (x – 1)2 + 2 ≤ 2 for every x ∈ R
The maximum value of f is attained when (x – 1) = 0
(x – 1) = 0, x = 1
Since, Maximum value of f = f (1) = – (1 – 1)2 + 2 = 2
Hence, function f does not have minimum value.
Answered by Aaryan | 1 year agoGiven the sum of the perimeters of a square and a circle, show that the sum of their areas is least when one side of the square is equal to diameter of the circle.
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