Divide 64 into two parts such that the sum of the cubes of two parts is minimum.

Asked by Aaryan | 1 year ago |  49

1 Answer

Solution :-

Suppose the two positive numbers be a and b. Given as a + b = 64 … (1)

We have, a3 + b3 is minima Assume that, S = a3 + b3 (From the equation 1)

S = a+ (64 – a)3 Thus, (d2S/da2) > 0  a = 32 will give the minimum value 

Thus, the two number will be 32 and 32

Answered by Sakshi | 1 year ago

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