1 Answer
Solution :-
Let us say the sum of perimeter of square and circumference of circle be L
Given sum of the perimeters of a square and a circle.
Assuming, side of square = a and radius of circle = r
Then, L = 4a + 2πr
= a = \( \dfrac{ (L – 2πr)}{4}\)… (1)
Let the sum of area of square and circle be S
So, S = a2 + πr2
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