Find the general solution of differential equations $$(x^2 + 1)\dfrac{dy}{dx }= 1$$

Asked by Aaryan | 1 year ago |  56

##### Solution :-

From the question it is given that,

$$(x^2 + 1)\dfrac{dy}{dx} = 1$$

By cross multiplication,

dy = $$\dfrac{dx}{(x^2 + 1)}$$

Integrating on both side, we get,

∫dy = ∫$$\dfrac{dx}{(x^2 + 1)}$$

We know that ∫$$\dfrac{dx}{(x^2 + 1)}$$ = tan -1 x + c

Therefore, y = tan -1 x + c

Answered by Aaryan | 1 year ago

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