From the question it is given that,
\( (x^2 + 1)\dfrac{dy}{dx} = 1\)
By cross multiplication,
dy = \( \dfrac{dx}{(x^2 + 1)}\)
Integrating on both side, we get,
∫dy = ∫\( \dfrac{dx}{(x^2 + 1)}\)
We know that ∫\( \dfrac{dx}{(x^2 + 1)}\) = tan -1 x + c
Therefore, y = tan -1 x + c
Answered by Aaryan | 1 year agoFind the particular solution satisfying the given condition \( (\dfrac{dy}{dx}) = (x – 1)\dfrac{dy}{dx} = 2x^3y\)
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