Differentiate with respect to x 3x + x3 + 33

Asked by Aaryan | 1 year ago |  50

1 Answer

Solution :-

Given:

f (x) = 3x + x3 + 33

Differentiate on both the sides with respect to x, we get

\( \dfrac{d}{dx}\) = (3x + x3 + 33)

We know that,

\( \dfrac{d}{dx}\)(xn) = \( nx^{n-1}\)

\( \dfrac{d}{dx}\) (constant) = 0

Derivative off (x) is \( 3^xlog_e3+3x^2\)

Answered by Aaryan | 1 year ago

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