Differentiate with respect to x xn loga x

Asked by Aaryan | 1 year ago |  156

1 Answer

Solution :-

Let us consider y = xn loga x

We need to find \( \dfrac{dy}{dx}\)

We know that y is a product of two functions say u and v where,

u = xn and v = loga x

y = uv

Now let us apply product rule of differentiation.

By using product rule, we get

\( \dfrac{dy}{dx}=x^{n-1}(nlog_ax+\dfrac{1}{log a})\)

Answered by Aaryan | 1 year ago

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