Let us consider y = x^{n} log_{a} x

We need to find \( \dfrac{dy}{dx}\)

We know that y is a product of two functions say u and v where,

u = x^{n} and v = log_{a} x

y = uv

Now let us apply product rule of differentiation.

By using product rule, we get

\( \dfrac{dy}{dx}=x^{n-1}(nlog_ax+\dfrac{1}{log a})\)

Answered by Aaryan | 1 year agoDifferentiate with respect to x (2x^{2} + 1) (3x + 2)