Find the equation of the plane passing through the point (1, 1, 1), (1, -1, 2) and (-2, -2, -2)

Asked by Aaryan | 1 year ago |  89

##### Solution :-

Given:

The three points are:

(1, 1, 1), (1, -1, 2) and (-2, -2, -2)

By using the formula, equation of plane passing through three points is given as:

$$\begin{vmatrix} x-1 & y-1 & z-1 \\[0.3em] 0& -2 & 1 \\[0.3em] -3 & -3 & 1 \end{vmatrix}$$

x – 3y – 6z + 8 = 0

Hence, the equation of plane is x – 3y – 6z + 8 = 0.

Answered by Sakshi | 1 year ago

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