Let us reduce the given equation 2x + 3y – z = 6 in intercept form:

Divide the given equation by 6, we get

\( \dfrac{x}{3}+ \dfrac{y}{2}+ \dfrac{z}{-6}=1\)

Now, compare equation 1 and 2, we get

a = 3, b = 2, c = -6

Therefore intercepts on the coordinate axes are 3, 2, -6.

Answered by Sakshi | 1 year agoA plane meets the coordinate axes in points A, B, C and the centroid of the triangle ABC is (1, -2, 3). Find the equation of the plane.

Write the equation of the plane whose intercepts on the coordinate axes are \( \dfrac{x}{a}+ \dfrac{y}{b}+ \dfrac{z}{c}=1\)

A plane meets the coordinate axes in points A, B, C and the centroid of the triangle ABC is (α,β,γ) .Find the equation of the plane

Reduce the equations of the planes in the intercept form and find its intercepts on the coordinate axes: 2x – y + z = 5

Reduce the equations of the following planes in the intercept form and find its intercepts on the coordinate axes: 4x + 3y – 6z – 12 = 0