Reduce the equations of the planes in the intercept form and find its intercepts on the coordinate axes: 2x – y + z = 5

Asked by Aaryan | 1 year ago |  180

##### Solution :-

Given:

The equation of plane is 2x – y + z = 5

Divide the given equation by 5, we get

$$\dfrac{x}{ \dfrac{5}{2}}+ \dfrac{y}{-5}+ \dfrac{z}{5}=1$$

Now, compare equation 1 and 2, we get

a = $$\dfrac{5}{2}$$, b = -5, c = 5

Therefore intercepts on the coordinate axes are $$\dfrac{5}{2}$$, -5, 5.

Answered by Sakshi | 1 year ago

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