\( \int \dfrac{1}{x^{\dfrac{3}{2}}}dx\)
Given equation can be written as
\( \int x^{\dfrac{-3}{2}}dx\)
On simplifying we get
\( -\dfrac{2}{\sqrt{x}}+c\)
\( \dfrac{x^{-\dfrac{3}{2}+1}}{-\dfrac{3}{2}+1}+c\)
On simplifying we get
\( -\dfrac{2}{\sqrt{x}}+c\)
Answered by Sakshi | 1 year ago