Firstly we need to convert the denominators to positive numbers.
\(\dfrac{ 7}{-18} =\dfrac{ (7 × -1)}{ (-18 × -1)} = \dfrac{-7}{18}\)
The denominators are 18 and 27
By taking LCM for 18 and 27 is 54
We rewrite the given fraction in order to get the same denominator
\( \dfrac{-7}{18} = \dfrac{(-7×3) }{ (18×3)} = \dfrac{-21}{54}\) and
\( \dfrac{ 8}{27} = \dfrac{(8×2) }{ (27×2) }=\dfrac{ 16}{54}\)
Since the denominators are same we can add them directly
\(\dfrac{ -21}{54} + \dfrac{16}{54 }= \dfrac{(-21 + 16)}{54} = \dfrac{-5}{54}\)
Answered by Sakshi | 1 year agoBy what number should 1365 be divided to get 31 as quotient and 32 as remainder?
Which of the following statement is true / false?
(i) \(\dfrac{ 2 }{ 3} – \dfrac{4 }{ 5}\) is not a rational number.
(ii) \( \dfrac{ -5 }{ 7}\) is the additive inverse of \( \dfrac{ 5 }{ 7}\)
(iii) 0 is the additive inverse of its own.
(iv) Commutative property holds for subtraction of rational numbers.
(v) Associative property does not hold for subtraction of rational numbers.
(vi) 0 is the identity element for subtraction of rational numbers.
If x = \( \dfrac{4 }{ 9}\), y =\( \dfrac{-7 }{ 12}\) and z = \( \dfrac{-2 }{ 3}\), then verify that x – (y – z) ≠ (x – y) – z
If x = \(\dfrac{ – 4 }{ 7}\) and y = \( \dfrac{2 }{ 5}\), then verify that x – y ≠ y – x
Subtract the sum of \(\dfrac{ – 5 }{ 7} and\dfrac{ – 8 }{ 3}\) from the sum of \(\dfrac{5 }{ 2} and \dfrac{– 11 }{ 12}\)