Firstly convert the denominator to positive number
\(\dfrac{ 11}{-39} = \dfrac{(11×-1)}{(-39×-1)} = \dfrac{-11}{39}\)
\( \dfrac{5}{26} +\dfrac{ -11}{39}\)
Now let us take the LCM for 26 and 39 which is 78
\(\dfrac{ (5×3)}{(26×3)} + \dfrac{(-11×2)}{(39×2)}\)
\( \dfrac{15}{78} + \dfrac{-22}{78}\)
Since the denominators are same we can add them directly
\(\dfrac{ (15-22)}{78} = \dfrac{-7}{78}\)
Answered by Sakshi | 1 year agoBy what number should 1365 be divided to get 31 as quotient and 32 as remainder?
Which of the following statement is true / false?
(i) \(\dfrac{ 2 }{ 3} – \dfrac{4 }{ 5}\) is not a rational number.
(ii) \( \dfrac{ -5 }{ 7}\) is the additive inverse of \( \dfrac{ 5 }{ 7}\)
(iii) 0 is the additive inverse of its own.
(iv) Commutative property holds for subtraction of rational numbers.
(v) Associative property does not hold for subtraction of rational numbers.
(vi) 0 is the identity element for subtraction of rational numbers.
If x = \( \dfrac{4 }{ 9}\), y =\( \dfrac{-7 }{ 12}\) and z = \( \dfrac{-2 }{ 3}\), then verify that x – (y – z) ≠ (x – y) – z
If x = \(\dfrac{ – 4 }{ 7}\) and y = \( \dfrac{2 }{ 5}\), then verify that x – y ≠ y – x
Subtract the sum of \(\dfrac{ – 5 }{ 7} and\dfrac{ – 8 }{ 3}\) from the sum of \(\dfrac{5 }{ 2} and \dfrac{– 11 }{ 12}\)