Firstly group the rational numbers with same denominators
\( \dfrac{4}{7} + \dfrac{-13}{7}+0 +\dfrac{ -8}{9 }+\dfrac{17}{21} \)
Now the denominators which are same can be added directly.
\( \dfrac{(4 + (-13))}{7} +\dfrac{ -8}{9} + \dfrac{17}{21}\)
\( \dfrac{(4-13)}{7} +\dfrac{ -8}{9} +\dfrac{ 17}{21}\)
\( \dfrac{-9}{7} +\dfrac{ -8}{9} +\dfrac{ 17}{21}\)
By taking LCM for 7, 9 and 21 we get, 63
\(\dfrac{ (-9×9)}{ (7×9)} + \dfrac{(-8×7)}{ (9×7) }+ \dfrac{(17×3)}{ (21×3)}\)
\( \dfrac{-81}{63} + \dfrac{-56}{63} + \dfrac{51}{63}\)
Since the denominators are same can be added directly
\( \dfrac{(-81+(-56)+ 51)}{63 }= \dfrac{(-81-56+51)}{63} = \dfrac{-86}{63}\)
Answered by Aaryan | 1 year agoBy what number should 1365 be divided to get 31 as quotient and 32 as remainder?
Which of the following statement is true / false?
(i) \(\dfrac{ 2 }{ 3} – \dfrac{4 }{ 5}\) is not a rational number.
(ii) \( \dfrac{ -5 }{ 7}\) is the additive inverse of \( \dfrac{ 5 }{ 7}\)
(iii) 0 is the additive inverse of its own.
(iv) Commutative property holds for subtraction of rational numbers.
(v) Associative property does not hold for subtraction of rational numbers.
(vi) 0 is the identity element for subtraction of rational numbers.
If x = \( \dfrac{4 }{ 9}\), y =\( \dfrac{-7 }{ 12}\) and z = \( \dfrac{-2 }{ 3}\), then verify that x – (y – z) ≠ (x – y) – z
If x = \(\dfrac{ – 4 }{ 7}\) and y = \( \dfrac{2 }{ 5}\), then verify that x – y ≠ y – x
Subtract the sum of \(\dfrac{ – 5 }{ 7} and\dfrac{ – 8 }{ 3}\) from the sum of \(\dfrac{5 }{ 2} and \dfrac{– 11 }{ 12}\)