Re-arrange suitably and find the sum $$\dfrac{-6}{7 }+ \dfrac{-5}{6} + \dfrac{-4}{9} +\dfrac{ -15}{7}$$

Asked by Sakshi | 1 year ago |  38

##### Solution :-

Firstly group the rational numbers with same denominators

$$\dfrac{-6}{7 }+\dfrac{ -15}{7}+ \dfrac{-5}{6} + \dfrac{-4}{9}$$

$$\dfrac{ (-6 -15)}{7} + \dfrac{-5}{6} +\dfrac{ -4}{9}$$

$$\dfrac{ -21}{7} + \dfrac{-5}{6} +\dfrac{ -4}{9}$$

$$\dfrac{ -3}{1} +\dfrac{ -5}{6} + \dfrac{-4}{9}$$

By taking LCM for 1, 6 and 9 we get, 18

$$\dfrac{ (-3×18)}{(1×18)} +\dfrac{ (-5×3)}{(6×3) }+ \dfrac{(-4×2)}{(9×2)}$$

$$\dfrac{ -54}{18} +\dfrac{ -15}{18} +\dfrac{ -8}{18}$$

Since the denominators are same can be added directly

$$\dfrac{ (-54-15-8)}{18 }= \dfrac{-77}{18}$$

Answered by Aaryan | 1 year ago

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