Firstly group the rational numbers with same denominators
\( \dfrac{-6}{7 }+\dfrac{ -15}{7}+ \dfrac{-5}{6} + \dfrac{-4}{9} \)
\(\dfrac{ (-6 -15)}{7} + \dfrac{-5}{6} +\dfrac{ -4}{9}\)
\(\dfrac{ -21}{7} + \dfrac{-5}{6} +\dfrac{ -4}{9}\)
\(\dfrac{ -3}{1} +\dfrac{ -5}{6} + \dfrac{-4}{9}\)
By taking LCM for 1, 6 and 9 we get, 18
\(\dfrac{ (-3×18)}{(1×18)} +\dfrac{ (-5×3)}{(6×3) }+ \dfrac{(-4×2)}{(9×2)}\)
\(\dfrac{ -54}{18} +\dfrac{ -15}{18} +\dfrac{ -8}{18}\)
Since the denominators are same can be added directly
\(\dfrac{ (-54-15-8)}{18 }= \dfrac{-77}{18}\)
Answered by Aaryan | 1 year agoBy what number should 1365 be divided to get 31 as quotient and 32 as remainder?
Which of the following statement is true / false?
(i) \(\dfrac{ 2 }{ 3} – \dfrac{4 }{ 5}\) is not a rational number.
(ii) \( \dfrac{ -5 }{ 7}\) is the additive inverse of \( \dfrac{ 5 }{ 7}\)
(iii) 0 is the additive inverse of its own.
(iv) Commutative property holds for subtraction of rational numbers.
(v) Associative property does not hold for subtraction of rational numbers.
(vi) 0 is the identity element for subtraction of rational numbers.
If x = \( \dfrac{4 }{ 9}\), y =\( \dfrac{-7 }{ 12}\) and z = \( \dfrac{-2 }{ 3}\), then verify that x – (y – z) ≠ (x – y) – z
If x = \(\dfrac{ – 4 }{ 7}\) and y = \( \dfrac{2 }{ 5}\), then verify that x – y ≠ y – x
Subtract the sum of \(\dfrac{ – 5 }{ 7} and\dfrac{ – 8 }{ 3}\) from the sum of \(\dfrac{5 }{ 2} and \dfrac{– 11 }{ 12}\)