Re-arrange suitably and find the sum \( \dfrac{4}{13 }+ \dfrac{-5}{8} + \dfrac{-8}{13} +\dfrac{9}{13}\)

Asked by Sakshi | 1 year ago |  82

1 Answer

Solution :-

Firstly group the rational numbers with same denominators

\(  \dfrac{4}{13 } + \dfrac{-8}{13} +\dfrac{9}{13}+ \dfrac{-5}{8} \)

\(\dfrac{ (4-8+9)}{13 }+ -\dfrac{5}{8}\)

\(\dfrac{ 5}{13} +\dfrac{ -5}{8}\)

By taking LCM for 13 and 8 we get, 104

\(\dfrac{ (5×8)}{(13×8)} + \dfrac{(-5×13)}{(8×13)}\)

\( \dfrac{40}{104} + \dfrac{-65}{104}\)

Since the denominators are same can be added directly

\(\dfrac{ (40-65)}{104} = \dfrac{-25}{104}\)

Answered by Aaryan | 1 year ago

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