Let us consider a number as x to be added to \( \dfrac{-5}{7}\)to get \( \dfrac{-2}{3}\)
So, \( \dfrac{-5}{7}+x= \dfrac{-2}{3}\)
x = \( \dfrac{-2}{3}+ \dfrac{5}{7}\)
let us take LCM for 3 and 7 which is 21
x = \(\dfrac{ (-2×7 + 5×3)}{21}\)
= \(\dfrac{ (-14 + 15)}{21}\)
= \(\dfrac{1}{21}\)
the required number is \( \dfrac{1}{21}\)
Answered by Aaryan | 1 year agoBy what number should 1365 be divided to get 31 as quotient and 32 as remainder?
Which of the following statement is true / false?
(i) \(\dfrac{ 2 }{ 3} – \dfrac{4 }{ 5}\) is not a rational number.
(ii) \( \dfrac{ -5 }{ 7}\) is the additive inverse of \( \dfrac{ 5 }{ 7}\)
(iii) 0 is the additive inverse of its own.
(iv) Commutative property holds for subtraction of rational numbers.
(v) Associative property does not hold for subtraction of rational numbers.
(vi) 0 is the identity element for subtraction of rational numbers.
If x = \( \dfrac{4 }{ 9}\), y =\( \dfrac{-7 }{ 12}\) and z = \( \dfrac{-2 }{ 3}\), then verify that x – (y – z) ≠ (x – y) – z
If x = \(\dfrac{ – 4 }{ 7}\) and y = \( \dfrac{2 }{ 5}\), then verify that x – y ≠ y – x
Subtract the sum of \(\dfrac{ – 5 }{ 7} and\dfrac{ – 8 }{ 3}\) from the sum of \(\dfrac{5 }{ 2} and \dfrac{– 11 }{ 12}\)