Let us consider a number as x to be added to \( \dfrac{2}{3} + \dfrac{3}{5}\) to get \( \dfrac{-2}{15}\)
\( x + ( \dfrac{2}{3} + \dfrac{3}{5}) = \dfrac{-2}{15}\)
By taking LCM of 3 and 5 which is 15 we get,
(15x + 2×5 + 3×3)15 = \( \dfrac{-2}{15}\)
15x + 10 + 9 = -2
15x = -2-19
x = \( \dfrac{-21}{15}\)
Further we can divide by 3 we get,
\( \dfrac{-21}{15}= \dfrac{-7}{5}\)
the required number is \( \dfrac{-7}{5}\)
Answered by Aaryan | 1 year agoBy what number should 1365 be divided to get 31 as quotient and 32 as remainder?
Which of the following statement is true / false?
(i) \(\dfrac{ 2 }{ 3} – \dfrac{4 }{ 5}\) is not a rational number.
(ii) \( \dfrac{ -5 }{ 7}\) is the additive inverse of \( \dfrac{ 5 }{ 7}\)
(iii) 0 is the additive inverse of its own.
(iv) Commutative property holds for subtraction of rational numbers.
(v) Associative property does not hold for subtraction of rational numbers.
(vi) 0 is the identity element for subtraction of rational numbers.
If x = \( \dfrac{4 }{ 9}\), y =\( \dfrac{-7 }{ 12}\) and z = \( \dfrac{-2 }{ 3}\), then verify that x – (y – z) ≠ (x – y) – z
If x = \(\dfrac{ – 4 }{ 7}\) and y = \( \dfrac{2 }{ 5}\), then verify that x – y ≠ y – x
Subtract the sum of \(\dfrac{ – 5 }{ 7} and\dfrac{ – 8 }{ 3}\) from the sum of \(\dfrac{5 }{ 2} and \dfrac{– 11 }{ 12}\)