Let us consider a number as x to be subtracted from \( \dfrac{3}{4} – \dfrac{2}{3}\) to get \( \dfrac{-1}{6}\)
So, \( ( \dfrac{3}{4} – \dfrac{2}{3})-x= \dfrac{-1}{6}\)
x =\( \dfrac{3}{4} – \dfrac{2}{3}+ \dfrac{1}{6}\)
Let us take LCM for 4 and 3 which is 12
\( x =\dfrac{ (3×3 – 2×4)}{12} + \dfrac{1}{6}\)
= \(\dfrac{ (9 – 8)}{12} + \dfrac{1}{6}\)
= \(\dfrac{ 1}{12} + \dfrac{1}{6}\)
Let us take LCM for 12 and 6 which is 12
= \(\dfrac{ (1×1 + 1×2)}{12}\)
= \( \dfrac{3}{12}\)
Further we can divide by 3 we get,
\( \dfrac{3}{12}= \dfrac{1}{4}\)
the required number is \( \dfrac{1}{4}\)
Answered by Aaryan | 1 year agoBy what number should 1365 be divided to get 31 as quotient and 32 as remainder?
Which of the following statement is true / false?
(i) \(\dfrac{ 2 }{ 3} – \dfrac{4 }{ 5}\) is not a rational number.
(ii) \( \dfrac{ -5 }{ 7}\) is the additive inverse of \( \dfrac{ 5 }{ 7}\)
(iii) 0 is the additive inverse of its own.
(iv) Commutative property holds for subtraction of rational numbers.
(v) Associative property does not hold for subtraction of rational numbers.
(vi) 0 is the identity element for subtraction of rational numbers.
If x = \( \dfrac{4 }{ 9}\), y =\( \dfrac{-7 }{ 12}\) and z = \( \dfrac{-2 }{ 3}\), then verify that x – (y – z) ≠ (x – y) – z
If x = \(\dfrac{ – 4 }{ 7}\) and y = \( \dfrac{2 }{ 5}\), then verify that x – y ≠ y – x
Subtract the sum of \(\dfrac{ – 5 }{ 7} and\dfrac{ – 8 }{ 3}\) from the sum of \(\dfrac{5 }{ 2} and \dfrac{– 11 }{ 12}\)