What number should be subtracted from $$\dfrac{3}{4} – \dfrac{2}{3}$$ to get $$\dfrac{-1}{6}$$?

Asked by Sakshi | 1 year ago |  102

##### Solution :-

Let us consider a number as x to be subtracted from $$\dfrac{3}{4} – \dfrac{2}{3}$$ to get $$\dfrac{-1}{6}$$

So, $$( \dfrac{3}{4} – \dfrac{2}{3})-x= \dfrac{-1}{6}$$

x =$$\dfrac{3}{4} – \dfrac{2}{3}+ \dfrac{1}{6}$$

Let us take LCM for 4 and 3 which is 12

$$x =\dfrac{ (3×3 – 2×4)}{12} + \dfrac{1}{6}$$

= $$\dfrac{ (9 – 8)}{12} + \dfrac{1}{6}$$

= $$\dfrac{ 1}{12} + \dfrac{1}{6}$$

Let us take LCM for 12 and 6 which is 12

= $$\dfrac{ (1×1 + 1×2)}{12}$$

$$\dfrac{3}{12}$$

Further we can divide by 3 we get,

$$\dfrac{3}{12}= \dfrac{1}{4}$$

the required number is $$\dfrac{1}{4}$$

Answered by Aaryan | 1 year ago

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