(i) \(\dfrac{ -4}{13} – \dfrac{-3}{26}\)
Let us take LCM for 13 and 26 which is 26
\(\dfrac{ (-4×2 + 3×1)}{26}\)
\( \dfrac{(-8+3)}{26} = \dfrac{-5}{26}\)
(ii) Let us consider the number to be added as x
\( \dfrac{-9}{14} + x = -1\)
x = \( -1 + \dfrac{9}{14}\)
By taking LCM as 14 we get,
\( x =\dfrac{ (-1×14 + 9)}{14}\)
= \(\dfrac{ (-14+9)}{14}\)
= \( \dfrac{-5}{14}\)
(iii) Let us consider the number to be added as x
\(\dfrac{ -7}{9} + x = 3\)
\( x = 3 +\dfrac{7}{9}\)
By taking LCM as 9 we get,
\( x = \dfrac{(3×9 + 7)}{9}\)
= \(\dfrac{ (27 + 7)}{9}\)
= \( \dfrac{34}{9}\)
(iv) Let us consider the number to be added as x
\( x + \dfrac{15}{23} = 4\)
\( x = 4 – \dfrac{15}{23}\)
By taking LCM as 23 we get,
\( x = \dfrac{(4×23 – 15)}{23}\)
= \(\dfrac{ (92 – 15)}{23}\)
=\( \dfrac{77}{23}\)
Answered by Aaryan | 1 year agoBy what number should 1365 be divided to get 31 as quotient and 32 as remainder?
Which of the following statement is true / false?
(i) \(\dfrac{ 2 }{ 3} – \dfrac{4 }{ 5}\) is not a rational number.
(ii) \( \dfrac{ -5 }{ 7}\) is the additive inverse of \( \dfrac{ 5 }{ 7}\)
(iii) 0 is the additive inverse of its own.
(iv) Commutative property holds for subtraction of rational numbers.
(v) Associative property does not hold for subtraction of rational numbers.
(vi) 0 is the identity element for subtraction of rational numbers.
If x = \( \dfrac{4 }{ 9}\), y =\( \dfrac{-7 }{ 12}\) and z = \( \dfrac{-2 }{ 3}\), then verify that x – (y – z) ≠ (x – y) – z
If x = \(\dfrac{ – 4 }{ 7}\) and y = \( \dfrac{2 }{ 5}\), then verify that x – y ≠ y – x
Subtract the sum of \(\dfrac{ – 5 }{ 7} and\dfrac{ – 8 }{ 3}\) from the sum of \(\dfrac{5 }{ 2} and \dfrac{– 11 }{ 12}\)