\(\dfrac{1}{7}× \dfrac{11}{2} – \dfrac{-2}{3} × \dfrac{5}{3}\)(divisible by 13, 2)
=\(\dfrac{ (1×11)}{(7×2)} – \dfrac{(-2×5)}{(3×3)}\)
= \(\dfrac{ 11}{14 }+ \dfrac{10}{9}\)
By taking LCM for 14 and 9 which is 126
= \(\dfrac{ ((11×9) + (10×14))}{126}\)
= \(\dfrac{ (99+140)}{126}\)
= \(\dfrac{ 239}{126}\)
Answered by Aaryan | 1 year agoBy what number should 1365 be divided to get 31 as quotient and 32 as remainder?
Which of the following statement is true / false?
(i) \(\dfrac{ 2 }{ 3} – \dfrac{4 }{ 5}\) is not a rational number.
(ii) \( \dfrac{ -5 }{ 7}\) is the additive inverse of \( \dfrac{ 5 }{ 7}\)
(iii) 0 is the additive inverse of its own.
(iv) Commutative property holds for subtraction of rational numbers.
(v) Associative property does not hold for subtraction of rational numbers.
(vi) 0 is the identity element for subtraction of rational numbers.
If x = \( \dfrac{4 }{ 9}\), y =\( \dfrac{-7 }{ 12}\) and z = \( \dfrac{-2 }{ 3}\), then verify that x – (y – z) ≠ (x – y) – z
If x = \(\dfrac{ – 4 }{ 7}\) and y = \( \dfrac{2 }{ 5}\), then verify that x – y ≠ y – x
Subtract the sum of \(\dfrac{ – 5 }{ 7} and\dfrac{ – 8 }{ 3}\) from the sum of \(\dfrac{5 }{ 2} and \dfrac{– 11 }{ 12}\)