\( \dfrac{1}{2} × \dfrac{1}{2} + \dfrac{5}{3}× \dfrac{7}{2} – \dfrac{13}{2} × \dfrac{1}{3}\)
\(\dfrac{ (1×1)}{(2×2)} + \dfrac{(5×7)}{(3×2)} – \dfrac{(13×1)}{(2×3)}\)
\(\dfrac{ 1}{4} + \dfrac{35}{6} – \dfrac{13}{6}\)
By taking LCM for 4 and 6 which is 24
\(\dfrac{ ((1×6) + (35×4) – (13×4))}{24}\)
\(\dfrac{ (6 + 140 – 52)}{24}\)
\(\dfrac{ 94}{24}\)
Further divide by 2 we get, \( \dfrac{ 94}{24}=\dfrac{ 47}{12}\)
Answered by Aaryan | 1 year agoBy what number should 1365 be divided to get 31 as quotient and 32 as remainder?
Which of the following statement is true / false?
(i) \(\dfrac{ 2 }{ 3} – \dfrac{4 }{ 5}\) is not a rational number.
(ii) \( \dfrac{ -5 }{ 7}\) is the additive inverse of \( \dfrac{ 5 }{ 7}\)
(iii) 0 is the additive inverse of its own.
(iv) Commutative property holds for subtraction of rational numbers.
(v) Associative property does not hold for subtraction of rational numbers.
(vi) 0 is the identity element for subtraction of rational numbers.
If x = \( \dfrac{4 }{ 9}\), y =\( \dfrac{-7 }{ 12}\) and z = \( \dfrac{-2 }{ 3}\), then verify that x – (y – z) ≠ (x – y) – z
If x = \(\dfrac{ – 4 }{ 7}\) and y = \( \dfrac{2 }{ 5}\), then verify that x – y ≠ y – x
Subtract the sum of \(\dfrac{ – 5 }{ 7} and\dfrac{ – 8 }{ 3}\) from the sum of \(\dfrac{5 }{ 2} and \dfrac{– 11 }{ 12}\)