By using the property
x × (y + z) = x × y + x × z
\(\dfrac{ -3}{7} × (\dfrac{ 12}{13}+ \dfrac{ -5}{6}) = \dfrac{ -3}{7} × \dfrac{ 12}{13} + \dfrac{ -3}{7} × -\dfrac{ -5}{6}\)
\(\dfrac{ -3}{7} × \dfrac{((12×6) + (-5×13))}{78} \)
\( = \dfrac{(-3×12)}{(7×13)} + \dfrac{(-3×-5)}{(7×6)}\)
\(\dfrac{ -3}{7}× \dfrac{(72-65)}{78} = \dfrac{-36}{91} + \dfrac{ 15}{42}\)
\(\dfrac{ -3}{7} ×\dfrac{ 7}{78}= \dfrac{(-36×6 + 15×13)}{546}\)
\(\dfrac{ -1}{26} = \dfrac{(196-216)}{546}\)
= \(\dfrac{ -21}{546}\)
=\( \dfrac{ -1}{26}\)
Hence, the property is verified.
Answered by Sakshi | 1 year agoBy what number should 1365 be divided to get 31 as quotient and 32 as remainder?
Which of the following statement is true / false?
(i) \(\dfrac{ 2 }{ 3} – \dfrac{4 }{ 5}\) is not a rational number.
(ii) \( \dfrac{ -5 }{ 7}\) is the additive inverse of \( \dfrac{ 5 }{ 7}\)
(iii) 0 is the additive inverse of its own.
(iv) Commutative property holds for subtraction of rational numbers.
(v) Associative property does not hold for subtraction of rational numbers.
(vi) 0 is the identity element for subtraction of rational numbers.
If x = \( \dfrac{4 }{ 9}\), y =\( \dfrac{-7 }{ 12}\) and z = \( \dfrac{-2 }{ 3}\), then verify that x – (y – z) ≠ (x – y) – z
If x = \(\dfrac{ – 4 }{ 7}\) and y = \( \dfrac{2 }{ 5}\), then verify that x – y ≠ y – x
Subtract the sum of \(\dfrac{ – 5 }{ 7} and\dfrac{ – 8 }{ 3}\) from the sum of \(\dfrac{5 }{ 2} and \dfrac{– 11 }{ 12}\)