By using the property
x × (y + z) = x × y + x × z
\( \dfrac{-8}{3} × ( \dfrac{5}{6} + \dfrac{-13}{12}) = \dfrac{-8}{3} × \dfrac{5}{6} + \dfrac{-8}{3} × \dfrac{-13}{12}\)
\(\dfrac{ -8}{3} × \dfrac{((5×2) – (13×1)}{12}\)
\( = \dfrac{(-8×5)}{(3×6)} +\dfrac{ (-8×-13)}{(3×12}\)
\(\dfrac{ -8}{3} × \dfrac{(10-13)}{12} = \dfrac{-40}{18} + \dfrac{104}{36}\)
\(\dfrac{ -8}{3} × \dfrac{-3}{12} = \dfrac{(-40×2 + 104×1)}{36}\)
\(\dfrac{ 2}{3} = \dfrac{(-80+104)}{36}\)
= \( \dfrac{ 24}{36}\)
= \( \dfrac{ 2}{3}\)
Hence, the property is verified.
Answered by Sakshi | 1 year agoBy what number should 1365 be divided to get 31 as quotient and 32 as remainder?
Which of the following statement is true / false?
(i) \(\dfrac{ 2 }{ 3} – \dfrac{4 }{ 5}\) is not a rational number.
(ii) \( \dfrac{ -5 }{ 7}\) is the additive inverse of \( \dfrac{ 5 }{ 7}\)
(iii) 0 is the additive inverse of its own.
(iv) Commutative property holds for subtraction of rational numbers.
(v) Associative property does not hold for subtraction of rational numbers.
(vi) 0 is the identity element for subtraction of rational numbers.
If x = \( \dfrac{4 }{ 9}\), y =\( \dfrac{-7 }{ 12}\) and z = \( \dfrac{-2 }{ 3}\), then verify that x – (y – z) ≠ (x – y) – z
If x = \(\dfrac{ – 4 }{ 7}\) and y = \( \dfrac{2 }{ 5}\), then verify that x – y ≠ y – x
Subtract the sum of \(\dfrac{ – 5 }{ 7} and\dfrac{ – 8 }{ 3}\) from the sum of \(\dfrac{5 }{ 2} and \dfrac{– 11 }{ 12}\)