Construct a quadrilateral ABCD in which AB = BC = 6 cm, AD = DC = 4.5 cm and ∠B = 120°.

Asked by Aaryan | 1 year ago |  77

##### Solution :-

The given details are AB = BC = 6 cm, AD = DC = 4.5 cm and ∠B = 120°.

Step 1- Draw a line AB = 6cm

Step 2- Construct and angle of 120° at B.

Step 3- Cut an arc of radius 6cm with B as the center to mark that point as C.

Here, AC is about 10.3cm in length which is greater than AD + CD = 4.5+4.5=9cm

We know that sum of the two sides of a triangle is always greater than the third side.

Construction is not possible.

Answered by Sakshi | 1 year ago

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