**(i) **11

We know that 69 and 96 are having ten’s and unit’s place interchanged, i.e., they are having reverse digits.

So, sum of digits is 15.

We know that when ab + ba is divided by 11 then quotient is (a + b).

The sum of 69 and 96 is divided by 11 then we get 15 (sum of digits) as our quotient.

**(ii) **15

We know that 69 and 96 are having ten’s and unit’s place interchanged, i.e., they are having reverse digits.

So, sum of digits is 15.

We know that when ab + ba is divided by (a + b) then quotient is 11.

The sum of 69 and 96 is divided by 15 (sum of digits) then we get 11 as our quotient.

Answered by Aaryan | 1 year agoWhich of the following numbers are divisible by 11:

**(i) **10835

**(ii)** 380237

**(iii)** 504670

**(iv) **28248

In each of the following replace * by a digit so that the number formed is divisible by 11:

**(i) **64 × 2456

**(ii) **86 × 6194

In each of the following replace * by a digit so that the number formed is divisible by 6:

**(i)** 97 × 542

**(ii)** 709 × 94

In each of the following replace × by a digit so that the number formed is divisible by 9

**(i) **49 × 2207

**(ii) **5938 × 623

If 42z3 is a multiple of 9, where z is a digit, what is the value of z?