(i) 11
We know that 69 and 96 are having ten’s and unit’s place interchanged, i.e., they are having reverse digits.
So, sum of digits is 15.
We know that when ab + ba is divided by 11 then quotient is (a + b).
The sum of 69 and 96 is divided by 11 then we get 15 (sum of digits) as our quotient.
(ii) 15
We know that 69 and 96 are having ten’s and unit’s place interchanged, i.e., they are having reverse digits.
So, sum of digits is 15.
We know that when ab + ba is divided by (a + b) then quotient is 11.
The sum of 69 and 96 is divided by 15 (sum of digits) then we get 11 as our quotient.
Answered by Aaryan | 1 year agoWhich of the following numbers are divisible by 11:
(i) 10835
(ii) 380237
(iii) 504670
(iv) 28248
In each of the following replace * by a digit so that the number formed is divisible by 11:
(i) 64 × 2456
(ii) 86 × 6194
In each of the following replace * by a digit so that the number formed is divisible by 6:
(i) 97 × 542
(ii) 709 × 94
In each of the following replace × by a digit so that the number formed is divisible by 9
(i) 49 × 2207
(ii) 5938 × 623
If 42z3 is a multiple of 9, where z is a digit, what is the value of z?