We know that the given number \( \overline{67y19}\) is divisible by 9.
And, if a number is divisible by 9 then sum of digits must be a multiple of 9.
i.e., 6 + 7+ y + 1 + 9 = multiple of 9
y + 23 = 0, 9, 18, 27…..
Here ‘y’ is a digit, where, ‘y’ can have values between 0 and 9.
y + 23 = 27 which gives y = 4.
y = 4
Answered by Aaryan | 1 year agoWhich of the following numbers are divisible by 11:
(i) 10835
(ii) 380237
(iii) 504670
(iv) 28248
In each of the following replace * by a digit so that the number formed is divisible by 11:
(i) 64 × 2456
(ii) 86 × 6194
In each of the following replace * by a digit so that the number formed is divisible by 6:
(i) 97 × 542
(ii) 709 × 94
In each of the following replace × by a digit so that the number formed is divisible by 9
(i) 49 × 2207
(ii) 5938 × 623
If 42z3 is a multiple of 9, where z is a digit, what is the value of z?