Given that the number  \( \overline{67y19}\)  is divisible by 9, where y is a digit, what are the possible values of y?

Asked by Sakshi | 1 year ago |  81

1 Answer

Solution :-

 

We know that the given number \( \overline{67y19}\) is divisible by 9.

And, if a number is divisible by 9 then sum of digits must be a multiple of 9.

i.e., 6 + 7+ y + 1 + 9 = multiple of 9

y + 23 = 0, 9, 18, 27…..

Here ‘y’ is a digit, where, ‘y’ can have values between 0 and 9.

y + 23 = 27 which gives y = 4.

y = 4

Answered by Aaryan | 1 year ago

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