If  $$\overline{98215x2}$$  is a number with x as its tens digit such that it is divisible by 4. Find all possible values of x.

Asked by Sakshi | 1 year ago |  51

##### Solution :-

We know that the given number $$\overline{98215x2}$$ is divisible by 4.

A number is divisible by 4 only when the number formed by its digits in unit’s and ten’s place is divisible by 4.

i.e., x2 is divisible by 4

Expanding x2,

10x + 2 = multiple of 4

Here x2 can take values 2, 12, 22, 32, 42, 52, 62, 72, 82, 92

So values 12, 32, 52, 72 and 92 are divisible by 4.

x can take values 1,3,5,7 and 9

Answered by Aaryan | 1 year ago

### Related Questions

#### Which of the following numbers are divisible by 11

Which of the following numbers are divisible by 11:

(i) 10835

(ii) 380237

(iii) 504670

(iv) 28248

#### In each of the following replace * by a digit so that the number formed is divisible by 11:

In each of the following replace * by a digit so that the number formed is divisible by 11:

(i) 64 × 2456

(ii) 86 × 6194

#### In each of the following replace * by a digit so that the number formed is divisible by 6:

In each of the following replace * by a digit so that the number formed is divisible by 6:

(i) 97 × 542

(ii) 709 × 94

#### In each of the following replace × by a digit so that the number formed is divisible by 9:

In each of the following replace × by a digit so that the number formed is divisible by 9

(i) 49 × 2207

(ii) 5938 × 623