Solve Cryptarithms:

Asked by Sakshi | 1 year ago |  82

##### Solution :-

Firstly let us solve for unit’s place,

B + 1 = 8

B = 7

Now let us solve for ten’s place,

A + B = 1

A + 7 = 1

A = -6 which is not possible.

Hence, A + B > 9

We know that now there should be one carry in hundred’s place and so we need to subtract 10 from ten’s place,

i.e., A + B – 10 = 1

A + 7 = 11

A = 11-7 = 4

Now to check whether our values of A and B are correct, we should solve for hundred’s place.

2 + A + 1 = B

2 + 4 + 1 = 7

7 = 7

i.e., RHS = LHS

A = 4 and B = 7

Answered by Aaryan | 1 year ago

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