1 Answer
Solution :-
Firstly let us solve for unit’s place,
A + B = 9 — (1)
With this condition we know that sum of 2 digits can be greater than 18.
So, there is no need to carry one from ten’s place.
Now let us solve for ten’s place,
2 + A = 0
Which means A = -2 which is never possible
Hence, 2 + A > 9
Now, there should be one carry in hundred’s place and hence we need to subtract 10 from ten’s place,
i.e., 2 + A – 10 = 0
A = 10-2 = 8
Now, substituting A=8 in 1,
A + B = 9
8 + B = 9
B = 9 – 8
B = 1
A = 8 and B = 1
Answered by Aaryan | 1 year agoRelated Questions
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