We have,
(3x + 4y)4 – x4
[(3x + 4y)2]2 – (x2)2
By using the formula (a2 – b2) = (a-b) (a+b)
[(3x + 4y)2 + x2] [(3x + 4y)2 – x2] [(3x + 4y)2 + x2] [3x + 4y + x] [3x + 4y – x] [(3x + 4y)2 + x2] [4x + 4y] [2x + 4y] [(3x + 4y)2 + x2] 8[x + 2y] [x + y]
Answered by Sakshi | 1 year ago