We have,
(a + 7) (a – 10) + 16
a2 – 10a + 7a – 70 + 16
a2 – 3a – 54
By considering, p+q = -3 and pq = -54
So we can replace -3a by 6a – 9a
-54 by 6 × -9
a2 – 3a – 54 = a2 + 6a – 9a – 54
= a (a + 6) -9 (a + 6)
= (a – 9) (a + 6)
Answered by Aaryan | 1 year ago